Chemistry, asked by asharmy15, 11 months ago

Number of molecules of water present in 180 u water is ?

Answers

Answered by safasiraj2002
1

Answer:

10

Explanation:

180u/18= 10 molucules

(h20= 2+16 =18)

Answered by KaurSukhvir
0

Answer:

The number of molecules of water (H₂O) present in 180 u water is equal to 6.023×10²⁴ molecules.

Explanation:

We know the molecular for molecular formula of water is H₂O.

The molecular mass of water = 18gmol⁻¹

The number of molecules in 1 mole of water = 6.023×10²³

It means, number of molecules in 18g of water = 6.023×10²³

We have given the mass of water 180u or 180g.

Therefore,

Number of molecules in 180g of water =\frac{ 6.023*10^{23}*180}{18}

                                                               = 60.23*10^{23}\\=6.023*10^{24}

Therefore, the no. of water molecules in 180g of water is equal to 6.023×10²⁴ molecules.

Similar questions