number of molecules present in 88g of co2
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1
Answer:
CO2 contains is 2×2×6.022×1023 atoms. Hence, the no. of oxygen atoms present in 88 g of CO2 is 2.41×1024 atoms. Now, we know that one molecule of CO contains one atom of oxygen.
Answered by
2
Answer:
given mass= 88 g
molar mass of CO2 = 12+16x2
= 12 + 32
= 44
no. of moles = given mass/ molar mass
no. of moles= 88/44
no. of moles = 2
no. of moles = no. of molecules/6.022 x 10^23
2 = no. of molecules/6.022 x 10^23
2 x 6.022 x 10^23 = no. of molecules
12.044 x 10^23= no. of molecules
Explanation:
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