number of moles in 25gm of CaCO3
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Answered by
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we know that
Ca=40gm
C=12gm
O=16gm
So
CaCO3=40+12+16*3
=52+48
=100gm
no. of moles=given mass/molar mass
=25/100
=1/4gm
=0.25gm
meghnamanavi:
atomic masses of C and O are 12 and 16 respectively. You wrote wrong.
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