Question

Number of moles in 52 gram of helium and 12.044 *10^23 number of helium atoms

Answer 1

No. of moles = 12.044 ×10^23/6.022 × 10^23. No. of moles = 2 moles c) Molar mass of oxygen gas = 16×2 = 32 g. Given mass = 160 g.

Answer 2

Answer:

No. of moles = 12.044 ×10^23/6.022 × 10^23. No. of moles = 2 moles c) Molar mass of oxygen gas = 16×2 = 32 g. Given mass = 160 g.