Number of moles of 2 Cr O2 7
ions that can be reduced by 1 mole of Sn2+ ions is :
(Cr2O7)2- + 14H+ + (3Sn)2+ ---> (2Cr)3+ + 7H2O + (3Sn)4+
(A) 3
/2
(B) 1/3
(C) 5
/6
(D) 6
/5
Answers
Answered by
0
Answer:
a)3/2 is the answer
Explanation:
so it sn2+ in one mole cr2o2 7 ions are highly reducing
Similar questions