Question

Number of moles of aluminium required for liberation of 136.2L of H_(2) at STP when aluminium reacts with excess of H_(2)SO_(4) .

Answer 1

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Answer 2

The number of moles of Aluminium (Al) required are 4.

Given:-

Volume of Hydrogen (H2) released = 136.2L

To Find:-

The number of moles of Aluminium (Al) required.

Solution:-

We can easily calculate the number of moles of Aluminium (Al) required by using these simple steps.

As

Volume of Hydrogen (H2) released = 136.2L

Volume at STP = 22.4L

The reaction taking place here =

2Al + 3H2SO4 ----> Al2(SO4)3 + 3H2

Here, first we need to find out the number of moles of H2

$n(H2) = \frac{136.2}{22.4}$

$n(H2) = 6$

In the reaction,

2 moles of Aluminium produces 3 moles of Hydrogen

or

3moles of Hydrogen are formed when 2 moles of Aluminium are reacted.

1 mole of Hydrogen = 2/3 moles of Aluminium

6 moles of Hydrogen = 2/3 × 6 moles of Aluminium

i.e.

Number of moles of Aluminium = 2/3 × 6 = 12/3 = 4

Hence, The number of moles of Aluminium (Al) required are 4.

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