Question

number of moles of electrons required to reduce one mole of NO3- to NO is​

Answer 1

I think you are talking about reduction of Cr2O7²⁻ to Cr3+.

◆ Answer -

1.2 moles e⁻

◆ Explanation -

Cr2O7²⁻ is reduced to Cr3+ according to following reaction -

Cr2O7²⁻ + 14H+ + 6e- → 2Cr3+ + 8H2O

That is 6 e- are required to reduce 1 mol of Cr2O7²⁻.

Electrons required to reduce 0.2 mol Cr2O7²⁻ are -

n' = 6 × 0.2

n' = 1.2 mol e-

Hence, 1.2 moles of electron required to reduce 0.2 mol of Cr2O7²⁻.

Hope you understand..

Answer 2

I hope it is help you.

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