Question

Number of moles of k2cr2o7 reduced by one mole of sn2+ ion is

Answer 1

Hey mate!!!

Here is ur answer

K2Cr2O7 ---------> 2K+ + CrO72-

Cr2O72−(aq) + 14H+ + 6e− → 2Cr3+(aq) + 7H2O (source wiki)

Sn2+ ------------> Sn4+ +2e-

You can see each Cr2O72- ion gains 6 electrons and Sn+2 loses two electrons each to form Sn4+

therefore you need 3 moles of Sn+2 to reduce 1 mole of K2Cr2O7

( so your answer is a 1/3 mole of K2Cr2O7)

full equation looks like this

Cr2O72- + 3Sn2+ +14H+ -------------------> 3Sn4+ + 2Cr3+ + 7H2O

also K2Cr2O7 = potassium dichromate and Sn = tin

❤ Hope u understand ❤