Question

. Number of moles of NaOH in 27 cm3 of 0.15 M.
NaOH solution is
(1) 0.15
(2) 27
0.00405
(4) 0.0405 M​

Answer 1

Answer:

Ans is 0.00405

Explanation:

Molarity = no of moles ×1000 /volume of solution

Given,

volume= 27cm^3

Molarity= 0.15M

now,

putting the values in the above formula

0.15= no of moles ×1000 / 27

no of moles = 0.15 ×27 /1000

no of moles= 0.00405.

(option 3 is correct)

Answer 2

Answer:

3. 0.00405 M

Given:

Molarity of NaOH solution = 0.15 M

Volume of NaOH solution = 27 $cm^{3}$

To find: Number of moles of NaOH

Explanation:

The number of moles and molarity of a solution are related as-

$Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution}$

Therefore, moles can be calculated by simply multiplying molarity of solution and volume of solution in Litre (L).

$Moles\ of\ NaOH\ = Molarity\ of\ NaOH\ solution$×$Volume\ of\ solution\ in\ L$

Now, in next step convert the volume from cm3 to L using the following conversion factor-  

$1 cm^{3} = 0.001 L$

Therefore,

Volume of solution in L = $27 cm^{3}$×$\frac{0.001\ L}{1\ cm^{3} } = 0.027\ L$

Finally, using the relation of moles and molarity, the number of moles of NaOH are determined as-

$Moles\ of\ NaOH\ = 0.15\ M$×$0.027\ L = 0.00405\ moles$

Hence, the correct option is (3) 0.00405 moles.

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