number of moles of oxygen atoms present in 350 mg of glucose is
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C₆H₁₂O₆
180 g of Glucose contains 6 moles of oxygen atoms
350 mg contains = 350 × 10⁻³ g × 6 / (180 g/mol) = 0.0116 mol
= 11.6 × 10⁻³ moles
11.6 × 10⁻³ moles of oxygen atoms are present in 350 mg of glucose.
180 g of Glucose contains 6 moles of oxygen atoms
350 mg contains = 350 × 10⁻³ g × 6 / (180 g/mol) = 0.0116 mol
= 11.6 × 10⁻³ moles
11.6 × 10⁻³ moles of oxygen atoms are present in 350 mg of glucose.
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