Question

Number of moles of

oxygen needed to produce
4 moles of water on
reacting with 4 moles of
hydrogen gas is
*
o im
1 mole
O
2 moles
3 moles
4 moles​

Answer 1

Answer:

2 moles is needed to produce

4 moles of water on

reacting with 4 moles of

hydrogen gas

Answer 2

ANSWER

21O2(g)+H2(g)⇌H2O(g)

As 1 mole of H2(g) reacts with 1/2 mole of O2(g)

∴3 moles of H2(g) will react with= 21×3moles of O2(g)

So, H2 is limiting reagent.

Now, 1 mole of H2(g) gives 1 mole of H2O(g)

∴ 3 moles of H2(g) gives 3 moles of H2O(g)

   Moles              21O2(g)+H2(g)⟶H2O(g)

 at t=0                 3                        3                            -

After reaction  3−23=1.5       3−3=0                 3

Total number of moles of gas present at the end of reaction is

⇒n=nO2+n