Question

Number of moles of solute present in 0.5 dm cube of 0.5 M solution is

Answer 1

Molarity=(no. of moles) /volume in litres

So no. of moles in such solution would be =(0. 5)(0.5)=0.25moles

As 1dm cube =1litre

Answer 2

Answer:

Number of moles of solute present in 0.5dm³ of 0.5M solution is 0.25 moles.

Explanation:

We have given,

The volume of the solution = 0.5dm³ = 0.5L

The molarity of the solution = 0.5M = 0.5mol/L

We have to find the number of moles of solute:

The equation use to calculate the molarity is the ratio of the moles of solute whose molarity is to be calculated and the volume of solution.

$M=\frac{\big n}{\big V}$

Here, M is the molarity of the solution,

n is the number of moles of the solute

V is the volume of solution in litres.

Now substitute the value of M and V in equation (1);

$0.5=\frac{\big n}{0.5}$

$n= (0.5)(0.5)$

$n= 0.25\; moles$

Therefore, the number of moles of solute is equal to 0.25 moles.