Chemistry, asked by sarfrajrockzzp7cbo7, 1 year ago

number of moles present in 0.5kgs of pure limestone(CaCO3)

Answers

Answered by adityasethi002

2

Gram molecular weight of caco3 =1mole
100gms (gram molecular weight )of caco3 = 1mole
0.5 kg or 500g = 1/100*500 moles
O.5 kg caco3 = 5 moles

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