Question

number of moles present in 250g of solvent when the molality is 2m is​

Answer 1

MOLALITY

Given

• Number of moles present (mol) = ?
• Mass of Solute (kg) = 250 g
• Molality (M) = 2 M

Convert the amount of mass from g to kg.

1 kg = 1000 g

(250 g) / (1000 g / 1 kg)

= 0.250 kg

Compute the number of moles present.

mol = Mkg

mol = (2)(0.250)

= 0.5 mol

$\:$

Hope it Helps

Answer 2

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