Question

Number of moles present in 5.85 kg
of NaCl?(Na-23.Cl-35)
​

Answer 1

Answer:

5.85 g of NaCl = 0.1 mol

1 L solution contain NaCl = 0.1 mol

1 ml solution contain NaCl = 0.0001 mol

one NaCl ionized Na+ and Cl- so that produce 2 ions

Total ion mole in 1 ml = 2x0.0001 mol

Number of iron in 1 ml=

2

x

0.0001

x

6.023

x

10

23

Number of iron in 1 ml =

1.2

x

10

20

ions

Explanation:

follow me

Answer 2

Answer:

 100 moles

Explanation:

Please refer the attachment !!!!!