Question

Number of moles present in a gas occupying 22400ml at STP

Answer 1

mole = given volume /22.4 L

here given volume = 22400 mL
we know, 1000 mL = 1 L
so, given volume = 22.4 L

hence,
no of mole = 22.4L/22.4L = 1

Answer 2

Answer: 1 mole of gas will occupy 22400mL of volume at STP.

Explanation:

According to the mole concept:

1 mole of any gas occupies 22.4L of volume at STP conditions.

We know the conversion factor:

1 Liter = 1000 mili Liters

So, 22.4 L = 22400 mL

Thus, 1 mole of gas will occupy 22400mL of volume at STP.