number of N atoms in 0.2 mole of N2H4
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1 mole of N2H4 weighs = 2×14+4×1
= 28+4 = 32 g
wt of 6.023×10²³ molecule of N2H4= 32g
N2 = 14×2=28g
Wt of 6.023×10²³atoms of N2 = 28g
Number of atoms in 1 mole = 6.023×10²³atoms
Number of N atoms in 0.2 mole = 6.023×10²³×0.2
= 1.2046×10²³ atoms
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