number of natural number such that it is 11 times the sum of its digits
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Given : natural number such that it is 11 times the sum of its digits
To Find : How many such numbers
Solution:
1 digit numbers not possible
2 digits numbers
Let say number is xy
sum of digits = x + y
number = 10x + y
10x + y = 11(x + y)
10x + y = 11 x + 11y
x = -10y
hence not possible
three digit numbers
11x + 11y + 11z = 100x + 10y + z
89x = y+ 10z
x = 1 , y = 9 , z = 8
198 is such a tumber
four digit Number
1000x + 100y + 10z + w = 11(x + y + z + w)
not possible
Hence 198 is the only number
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