Question

number of Neutron present in 0.5 mole of NaOH​

Answer 1

Hello there,

Number of neutrons can be found out by the formula as,

Number of n=moles ×NA × number of neutrons in a the given compound

So number of neutrons of Na,O and H will be for Na=12

For O=8

For H=0

So,the number of neutrons of the given compound is=0.5×NA×(12+8+0)

0.5NA×20=10NA

10×6.022×10^23=6.022×10^24

Thank you