number of neutrons present in 18 mL water is
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Explanation:
The Answer is 4.8×10^24 nuetrons
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Mass of 18ml water=18gm
no. of moles=
18
18
=1mole
Total molecules=6.023×10
23
×1=6.023×10
23
One molecule water have 8 neutrons
Total number of neutrons==8×6.023×10
23
=48.16×10
23
Since m=ρ×V,
m=18 g
Hence number of molecules of H
2
O=1×6.022×10
23
Number of moles=
18
18
=1
Number of neutrons present in a molecule of H
2
O=2+6=8
Number of neutrons present in 6.022×10
23
molecules of 8×6.022×10
23
=4.8176×10
24
no. of moles=
18
18
=1mole
Total molecules=6.023×10
23
×1=6.023×10
23
One molecule water have 8 neutrons
Total number of neutrons==8×6.023×10
23
=48.16×10
23
Since m=ρ×V,
m=18 g
Hence number of molecules of H
2
O=1×6.022×10
23
Number of moles=
18
18
=1
Number of neutrons present in a molecule of H
2
O=2+6=8
Number of neutrons present in 6.022×10
23
molecules of 8×6.022×10
23
=4.8176×10
24
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