Number of nitrogen atoms present in 1.4g n2 gas
Answers
Answered by
49
Answer:
Number of atoms =6.022 × 10²³
Explanation:
Given weight of N₂ gas = 1.4 g
Molar mass of N₂ gas = 28 g
So, mole = given mass/ molar mass
⇒ mole = 1.4/28 = 1/20 mole
Now, number of molecules = mole × avogadro number
⇒ number of molecules = 1/20 × 6.022 × 10²³
⇒ number of molecules = 3.011 × 10²²
Now, we are asked for number of atoms. In N₂, there are 2 atoms, so to obtain number of atoms we will multiply with 2 in number of molecules.
⇒ number of atoms = 2 × 3.011 × 10²²
⇒ number of atoms = 6.022 × 10²²
⇒ number of atoms = 6.022 × 10²³
Anonymous:
Hey bro ! Molar mass / Molecular mass is 28 .
Answered by
1
Answer:
ans is 6.022×10 raise to 23
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