Question

Number of nitrogen atoms present in 1.4g n2 gas

Answer 1

Answer:

Number of atoms =6.022 × 10²³

Explanation:

Given weight of N₂ gas = 1.4 g

Molar mass of N₂ gas = 28 g

So, mole = given mass/ molar mass

⇒ mole = 1.4/28 = 1/20 mole

Now, number of molecules = mole × avogadro number

⇒ number of molecules = 1/20 × 6.022 × 10²³

⇒ number of molecules = 3.011 × 10²²

Now, we are asked for number of atoms. In N₂, there are 2 atoms, so to obtain number of atoms we will multiply with 2 in number of molecules.

⇒ number of atoms = 2 × 3.011 × 10²²

⇒ number of atoms = 6.022 × 10²²

⇒ number of atoms = 6.022 × 10²³

Answer 2

Answer:

ans is 6.022×10 raise to 23