number of nitrogen atoms present in 1.4g of n2is
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Molar mass of nitrogen is 28. Hence 28 gm of nitrogen = 6.022 × 10^23 molecules of hydrogen = 12.044× 10^ 23 atoms of nitrogen. 1.4 gm nitrogen = 6.022 × 10^22 atoms of nitrogen
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Answer:
number of nitrogen present -28
Explanation:
Molar mass of nitrogen is 28. Hence 28 gm of nitrogen = 6.022 × 10^23 molecules of hydrogen = 12.044× 10^ 23 atoms of nitrogen. 1.4 gm nitrogen = 6.022 × 10^22 atoms of nitrogen.
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