Question

Number of Nitrogen molecules in 1.12 cm³ at STP is; a) 6.022 x 10²⁰ b) 3.011 x 10¹⁸ c) 6.022 x 10¹⁸ d) 3.022 x 10²⁰​

Answer 1

Answer:

Option b) $3.011 * 10^{18}$ is correct.

Explanation:

moles of Nitrogen at STP = $\frac{V}{22.4}$

$= \frac{1.12}{(22.4* 1000)}$

$= 5*10^{-5}$

No. of molecules $= 5*10^{-5}$ x $6.023 * 10^{23}$

                             $= 3.011 * 10^{18}$  molecules.

Answer 2

Given-Number of Nitrogen molecules in $1.12 cm^3$ at STP is; a) $6.022 \times 10^{20}$ b) $3.011 \times 10^{18}$ c)  $6.022 x 10^{18}$d) $3.022 \times 10^{20}$

Answer-option (b)      $3.011 \times 10^{18}$ is correct

Explanation- Moles of nitrogen at STP$=\frac{V}{22.4}$

$=\frac{1.12}{(22.4\times 1000)} \\=5\times 10^{-5}$

Number of molecules $=5\times1 10^{-5}\times 6.023\times 10^{23}$

$=3.011\times 10^{18}$ Molecule.

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