Question

Number of nuetrons present in 1 mole of H2S is:​

Answer 1

1 mole = 6.022×10²³ particles

No of molecules of H2S = 6.022×10²³

No of neutrons of H = 0 (since H has no neutrons)

No of Sulphur atoms = 6.022×10²³

No of neutrons in 1 S atom = 16

Total no of S neutrons = 16×6.022×10²³ = 96.352×10²³ = 9.6352×10²⁴

Total no of neutrons in 1 mole of H2S = 9.6352×10²⁴

Answer 2

Answer:

The number of neutrons present is  $9.63 * 10^{24}$.

Explanation:

In 1 mole of a compound, there are $6.02 * 10^{23}$ atoms, molecules, or ions.

In 1 mole of $H_{2}S$ there are $6.02 * 10^{23}$ molecules.

We know that hydrogen does not have a neutron.

The atomic number of sulphur is - 16

The mass number of sulphur is - 32

The neutron number of sulphur is - 32 - 16 = 16

The total number of sulphur present- $6.02 * 10^{23}$

The total number of neutrons is-

$(6.02 * 10^{23}) * 16$

$= 9.63 * 10^{24}$ neutrons

Conclusion:

 $9.63 * 10^{24}$ neutrons are present in one mole of $H_{2}S$.