Question

Number of O atoms in 10.037g of CuSO4.5H2O

Answer 1

Molar mass of CuSO4.5H2O = 250 No. of moles = 10.037 / 250 = 0.040 No. of molecules = 0.040 * 6.02 * 10^23 = 2.417 x 10^22 1 molecule of CuSO4.5H2O gives 9 O atoms --> No. of O atoms = 2.417 x 10^22 x 9 = 2.175 x 10^23

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Answer 2

Answer:

Molar mass of CuSO4.5H2O = 250 No.

of moles = 10.037 / 250 = 0.040 No. of

molecules = 0.040 * 6.02*10^23 = 2.417 x

10^22 1 molecule of CuSO4.5H2O gives 9 O atoms --> No. of O atoms = 2.417 x 10^22

x 9 = 2.175 x 10^23

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