Number of of natural numbers between hundred and thousand such that at least one of their digit is 7
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Answered by
24
Answer:
252
Step-by-step explanation:
Total number of 3 digit numbers having atleast one of their digits as 7
= (Total numbers of 3 digit numbers) – (Total number of 3 digit numbers in which 7 does not appear at all).
= (9 × 10 × 10) – (8 × 9 × 9) = 900 – 648 = 252.
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