Number of orbitals required to place all electrons of an element with atomic no 30
A .13
B.15
C.9
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Answer:
option B is correct
Explanation:
atomic number =30
electronic configuration =1s^22s^22p63s^23p^6
4s^23d^10
so in s subshell there are 1 orbital
in p subshell there are 3 orbital
in d subshell there are 5 orbital
so there are 4 s subshell ,2 p subshell ,1 d subshell
so 4 ×1 =4 ,2×3=6, 1×5=5
15 orbitals required
hope you understand
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