Number of oxygen atom in 40gm of SO3
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hii friend....
no of mole of SO3 = 40/80 = 0.5 mole
then mole of O = 0.5 × 3 = 1.5 mole
then no of oxygen atom is = 1.5 × 6.02 × 10^23
☺☺
no of mole of SO3 = 40/80 = 0.5 mole
then mole of O = 0.5 × 3 = 1.5 mole
then no of oxygen atom is = 1.5 × 6.02 × 10^23
☺☺
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Explanation:
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