Number of oxygen atoms present in 1 gram of calcium carbonate are
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Answered by
4
Answer:
100 g of Calcium Carbonate (100,000 mg of Calcium Carbonate) has 3 moles of Oxygen atoms = 3 x 6.022 x 10^23 Oxygen atoms.
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0
Answer:
1.8×10²²
Explanation:
0.03 moles of oxygen atoms which is equal to 0.03×6.02×1023=1.8×10²² oxygen atoms.
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