Question

number of oxygen atoms present in 10.6g of Na2Co3

Answer 1

Gram molecular mass of Na2Co3 =2(23)+12+3(16)=106 gm
106 gm of Na2Co3 contains 3(16) gm =48 gm of oxygen.
10.6 gm of Na2Co3 contains oxygen =(48/106)*10.6=4.8 GM
16 GM of oxygen =6.023*10^23 atoms

4.8 gm of oxygen =(6.023*10^23/16)*4.8 atoms


...hope it helps....

Answer 2

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Gram molecular mass of Na2Co3 =2(23)+12+3(16)=106 gm
106 gm of Na2Co3 contains 3(16) gm =48 gm of oxygen.
10.6 gm of Na2Co3 contains oxygen =(48/106)*10.6=4.8 GM
16 GM of oxygen =6.023*10^23 atoms

4.8 gm of oxygen =(6.023*10^23/16)*4.8 atoms

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