number of oxygen atoms presents in224 ml water at STP
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no of moles of O2=volume /22.4
no of moles=224/22.4=0.1 mole ofO2
no of O atoms in one molecule =2
therefore,no of O atoms in 0.1 mole of O2=2×0.1× NA(NA=avagadro constant)
=1.2044×10^23 atoms of O
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