Question

Number of oxygen present in 224 ml of O2 at STP is ?

Answer 1

Explanation:

Therefore 0.16g is the answer.

Answer 2

Answer:

There are  $6.02*10^{21}$ molecules are present in 224ml of oxygen.

Calculation:

As we know that the volume of 1 mole of any substance at STP is 22400ml.

To find the number of oxygen molecules present in 224ml at STP, we first find the moles

1 mole of Oxygen molecules at STP = 22400ml

$x$ mole of Oxygen at STP = 224 ml of Volume

$x * 22400 = 1 * 224$

$x = \frac{224}{22400}$

$x = 0.01 mol$ of oxygen molecules

We can now find the number of molecules when we multiply moles by the avogadro's constant.

$6.02*10^{23}$ molecules = 1 mole

$x$ molecules = 0.01 moles

$6.02*10^{23} * 0.01$ = $1 * x$

$6.02*10^{21} = x$

In 224ml of oxygen, $6.02*10^{21}$ molecules are present.