Math, asked by sonalidehariya39, 2 months ago

number of permutations formed by taking all letter of the word BHOPAL is:​

Answers

Answered by luciddreamsofficial0
0

Answer:

Factorial Six

Step-by-step explanation:

No. of letters=6

Therefore, no. of permutations of the word

'BHOPAL'= 6

P

6

= 6!/6-6!

= 6!/0!

= 6!(Since 0!=1)

=6×5×4×3×2×1

= 720

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Answered by saritasingh876751256
0

Answer:

Here, the number of letters are 6 and every time we take 6 letters. Hence, required number of = ⌊6 = 6 × 5 × 4 × 3 × 2 × 1 = 720Read more on Sarthaks.com - https://www.sarthaks.com/731958/how-many-words-can-be-formed-using-letters-of-bhopal-a-124-b-240

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