Question

Number of photon coming out per sec from the bulb of 100 watt.If it is 50% efficient and wavelength is 600nm

Answer 1

Answer:

Explanation:

Recall E=hcλ

E=(6.626×10−34)(3.0×108)560×10−9

E=3.550×10−19J

Each photon carries 3.550×10−19J of energy.

A 100W source means that it outputs 100J of energy every second.

number of photons emitted = total energy output in one second / energy carried per photon

n=1003.550×10−19=2.8×1020 (2sf)

Answer 2

Answer:

Hope it's gonna help uhh