Question

number of photon emitted in 5hrs by a 50 watt sodium lamp.(lamda=5893 angstron.).....plz answer me fast.....​

Answer 1

Answer:

3.21×$10^{24}$

Explanation:

Energy of photon, E = hν = h(c/λ) = 3.374 x 10-19 J

[It is known that, h = 6.626 x 10-34 m² kg/s and c = 3 x 108 m/s]

Number of photons emitted by the sodium lamp in one second = [60 / 3.374 x $10^{-19}$

∴ No. of protons emitted in 5 hours =  [(60 x 5 x 3600)/ (3.374 x $10^{-19}$)] = 3.21×$10^{24}$