Math, asked by NaveenBalaji96, 10 months ago

number of points in R in which f(x)=|x-1|+|x-3|+sinx is not differnetiable

Answers

Answered by muthyalasravani1729
0

Answer:

at x=1 (or) x=3 the function is not differentiable

Step-by-step explanation:

f(x)= l x-1 l+l x-3 l + sinx

these cannot be differential able at the point 1,3

let differentiate the given function

then we get

f'(x)= [ (|x-1|)/(x-1) ]+[ (|x-3|)/(x-3) ]+cosx

{ here differentiate of |x| is [(|x|)/x] }

if denominator is zero then the function is not differentiable

the denominator will be zero at x=1 (or) x=3

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