number of polynomials having -2 and 5 as zeroes are??
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Answered by
0
Answer:
-2
Step-by-step explanation:
Answered by
4
Answer:
Step-by-step explanation:
Let p(x) = ax2 + bx + c be the required polynomial whose zeroes are -2 and 5.
sum of zeroes = -b/a
-b/a -2+5= -3/1 = -(-3/1)
product of zeroes = c/a
c/a = -2*5 = -10/1
Hence, the required number of polynomials are infinite i.e., more than 3.
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