Question

 number of possible digits for x such that 10x 78x is divisible by 3 is​

Answer 1

Step-by-step explanation:

We know that the given number

18x71

is divisible by 3.

And, if a number is divisible by 3 then sum of digits must be a multiple of 3.

i.e., 1+8+x+7+1= multiple of 3

x+17=0,3,6,9,12,15…

Here x is a digit, where, x can have values between 0 and 9.

x+17=18 which gives x=1.

x+17=21 which gives x=4.

x+17=24 which gives x=7.

Hence, x=1,4,7.

Answer 2

Answer:

3

Step-by-step explanation:

divisibilty criteria of 3= sum of all digits should be equal to 3

10x78x=10+7+8=25=2+5=7

subtract by three further till you get remainder as 1

7-3=4

4-3=1 (3times)

7,4,1 = 3 possible digits