Question

Number of real roots of equation 3x^2+4x+5=0 have

Answer 1

Step-by-step explanation:

HERE'S the answer to ur question dear sir.

hope it is helpful

plz mark it as a brainlist answer.

.......

....

.

.

.

.

.

.

Answer 2

Answer:

Step-by-step explanation:

Given: The equation is $3x^2+4x+5=0$

Find: To find the number of real roots of equation

Solution: The standard form of the quadratic equation $ax2 + bx + c = 0$and the formula used is

$x$ = [-b ± √(b2 - 4ac)]/ 2a

It is given that

$3x2 - 4x + 5 = 0$

Here a = 3, b = -4 and c = 5

Substituting these values in the formula

$x$ = [-(-4) ± √((-4)2 - 4 × 3 × 5)] /  (2 × 3)

By further simplification

$x$ = [4 ± √(16 - 60)] / 6

$x$ = [4 ± √-44] / 6

So we get,

$x$ = [4 ± 2√-11] / 6

$x$ = [2 ± i √11] / 3

Also the discriminant is b2 - 4ac = -44 < 0. Thus we have imaginary roots.

Hence the number of real roots of equation $3x^2+4x+5=0$ is nil.

#SPJ2