Math, asked by gvsk500, 10 months ago

number of real roots of equation x-1^2+x-2^2+x-3^2=0

Answers

Answered by bhatlu25p1ml0y
0

(x-1)^2+(x-2)^2+(x-3)^2=0

3x^2 - 12x + 12 =0

3x^2 - 6x - 6x + 12 = 0

(3x -6) (x-2) = 0

x = 2,2

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