Question

Number of real roots of the equation

(x+a)^2- X^2= 0 is​

Answer 1

Answer

Given equation:

x  

2

−3∣x∣+2=0

When x>0, we have

x  

2

−3x+2=0

⇒(x−2)(x−1)=0

⇒x=2 or x=1

and when x<0,

x  

2

+3x+2=0

or, (x+2)(x+1)=0

or, x=−2 or x=−1

Therefore, number of real roots is 4.

Answer 2

Step-by-step explanation:

(x+a)^2-x^2=0

x²+a²+2ax-x²=0

a²+2ax=0

a=2 and x could be -1