Math, asked by sureshthakur89899898, 12 hours ago

Number of real solution(s) of the equation
tan^-1(x-1/x+2)+tan^-1(x+1/x+2)=π/4 is​

Answers

Answered by dv44601
0

Answer:

tan^-1(x-1/x+2)+tan^-1(x+1/x+2)=π/4

tan^-1[(x-1/x+2+x+1/x+2)/1-(x-1/x+2)*(x+1x+2)]

tan^-1[(2x/x+2)/(x+2)^2-(x+1)/(x+2)^2

tan^-1[(2x(x+2)/(x+2)^2-(x+1)]

tan^-1[(2x^2+4x)/x^2+4x+4-x]

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