Math, asked by ankesh111, 3 months ago

Number of real solution(s) of x^2 - 4x+ 6 = 2 + root ( x-2) is /are ?

Answers

Answered by PardhivPrasadK
0

Answer:

Number of Real solutions are 2. They are 2,3.

Step-by-step explanation:

getting 2 to LHS simplifies the equation as x²-4x+4 = root(x-2).

=> (x-2)² = root(x-2)

=> (x-2)⁴- (x-2) = 0.

further simplifying that we get 3 as another real root and two imaginary roots.

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