Question

Number of sides of polygon if there are 44 diagonals

Answer 1

no of diagonals = n(n-3)/2
44 x 2 = n(n-3)
88 = n(n-3)
11 × 8 = n(n-3)
n = 11
sum of interior angles of polygons = (n-2) × 180
= (11-8) x 180
= 1620
no of sides of polygon = ( 1620/180) = 9