Chemistry, asked by Aoikatsuki, 1 year ago

Number of spectral lines in balmer series when an electron return from 7 th orbit to 1st orbit of hydrogen atom are.......( Plzzzzz show calculation)

Answers

Answered by atharv2000
66
(7-1)(7-1+1) /2
(6)(7) /2
42/2
21 this is total no of spectral line

spectral line for balmer series = (7-2) =5

Aoikatsuki: Which formula
atharv2000: (n1-n2) (n1-n2 -1) /2
Aoikatsuki: "spectral line for balmer series = (7-2) =5" how did this happen
atharv2000: and no of spectral line for particular series = n2-n1
atharv2000: for bamer series n1=2
atharv2000: got it?
Aoikatsuki: Yeah...thanx
ahmedpatel2310pcmwvo: but how u done “7”
ahmedpatel2310pcmwvo: n =2 okay but why 7
priya090: hii
Answered by RomeliaThurston
106

Answer: The number of spectral lines in balmer series for the given transition are 5.

Explanation:

We are given:

An electron is undergoing a transition from n = 1 to n = 7.

  • To calculate the total number of spectral lines in the transition, we use the formula:

N=\frac{(n_2-n_1)(n_2-n_1+1)}{2}

where,

n_1 = lower energy level = 1

n_2 = higher energy level = 7

Putting values in above equation, we get:

N=\frac{(7-1)(7-1+1)}{2}=21

So, the total number of spectral lines in the transition are 21.

  • To calculate the number of spectral lines in a particular series, we use the formula:

N=(n_2-n_1)

where,

n_1 = lower energy level = 2 (for Balmer)

n_2 = higher energy level = 7

Putting values in above equation, we get:

N=(7-2)=5

Hence, the number of spectral lines in balmer series for the given transition are 5.

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