number of students who have opted the subjects a, b and c are 60, 84 and 108 respectively the examination is to be conducted for these students such that only the students of the same subject are allowed in one room. also the number of students in each room must be the same. what is the minimum number of rooms that should be arranged to meet all these conditions? (a) 28 (b) 60 (c) 12 (d) 21
Answers
Answered by
2
Answer:
Option C is correct .i.e., 12
Step-by-step explanation:
No of student in subject a = 60
No of student in subject b = 84
No of student in subject c = 108
For the require answer we have to find HCF of 60 , 84 , 108
as HCF is the no which divides the each no.
we find HCF by prime factorization method.
Prime factorization of 60 = 2 × 2 × 3 × 5
Prime factorization of 84 = 2 × 2 × 3 × 7
Prime factorization of 108 = 2 × 2 × 3 × 3 × 3
HCF = 2 × 2 × 3 = 12
Therefore, Option C is correct .i.e., 12 rooms should be arranged to meet all conditions.
Answered by
0
Answer:
Step-by-step explanation:
Hcf of 60,84 and 108 is 12.
so 12 students in each room.
60+84+108=252/12=21
hence, d is the answer
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