Number of terms in the expansion (x2+x+1)2
are
Answers
Answered by
1
Step-by-step explanation:
(a±b)
n
=
n
C
0
a
n
b
0
±
n
C
1
a
n−1
b
1
+
n
C
2
a
n−2
b
2
±....+
n
C
n
a
0
b
n
(x
2
−a
2
)
5
=
5
C
0
x
10
−
5
C
1
x
8
a
2
+
5
C
2
x
6
a
4
−
5
C
3
x
4
a
6
+
5
C
4
x
2
a
8
−
5
C
5
x
0
a
10
=x
10
−5x
8
a
2
+10x
6
a
4
−10x
4
a
6
+5x
2
a
8
−x
0
a
10
Middle term = 10x
6
a
4
,−10x
4
a
6
Answered by
0
Answer:
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