Question

number of total atoms in N2O5 . if weight of of N2O5 is 10.8 gram

plz don't give useless answers its urgent.​

Answer 1

Answer:

4.2×10^23 atoms

Explanation:

Molar mass of N2O5 is 108g

And given mass of N2O5 is 10.8g

So number of moles of N2O5 present is

$n = \frac{mass}{molar \: mass} = \frac{10.8}{108} = 0.1$

Now 1 mole of gas has 6.02×10^23 molecules of that gas

So 0.1 mole has 6.02×10^22 molecules of N2O5

Now, 1 molecule of N2O5 has 7 atoms so 6.02×10^22 molecules will have 7×6.02×10^22 atoms

So number of atoms are

4.2×10^23 atoms