Question

Number of valence electrons in phosphonium ions

Answer 1

Answer:

8

Explanation:

PH4+

1 phosphorous atom = 5 valence electrons

1 hydrogen atom = 1 valence electron, therefore ...

4 hydrogen atoms = 4 valence electrons

The positive charge at the end means we have to remove 1 valence electron.

Together, we use arithmetic to solve: 5 + 4 - 1 = 8 valence electrons.

Answer 2

Number of valence electrons in phosphonium ions is 8

Explanation:

• phosphonium ions $PH4^{+}$
• In phosphonium cation the polyatomic cations are described with the chemical formula $PR4^{+}$ where R will be a hydrogen or an alkyl, aryl, or halide group.
• These ions will have tetrahedral structures.
• The salts  formed with phosphonium ions will be colorless or will have  the color of the anions
• Phosphonium ions will form Phosphonium salt.
• It is those salts  in which the cation will have a tetravalent phosphorous atom which bears a positive formal charge.
• 1 phosphorous atom = 5 valence electrons
• 1 hydrogen atom = 1 valence electron,
• 4 hydrogen atoms = 4 valence electrons
• The positive charge at the end means we have to remove 1 valence electron.
• Together, we use arithmetic to solve: 5 + 4 - 1 = 8 valence electrons.
• Number of valence electrons in phosphonium ions is 8

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