number of water molecules in a drop of weighing 0.018g is
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6.023 × 10 ^20 molecules
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Answer- First of all, you should be clear with the following formulae:-
1. No. of moles (n)= Given mass (m) ÷ Molar mass (M)
2. No. of moles= No. of particles (N) ÷ N₀
3. No. of atoms/molecules= m÷M × N₀
In this question, we are given the mass of drops of water and we have to find the number of water molecules. So, we will use the 3. formula.
So,
Given mass (m)= 0.018 g
Molar mass of water (M)= 2[H] + [O] = 2[1] + 16 = 2+16=18 g
No. of water molecules= 0.018÷ 18 × 6.022 × 10^23
= 6.022×10^20 molecules
So, no. of water molecules = 6.022×10^20 molecules
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